How many moles of KMnO₄ are required to oxidize 0.5 moles of FeSO₄ in the presence of sulfuric acid?
- 0.5
- 0.1
- 0.2
- 2.5
📝 Batafsil tushuntirish
Redox: 10FeSO₄ + 2KMnO₄ + 8H₂SO₄ → 5Fe₂(SO₄)₃ + 2MnSO₄ + K₂SO₄ + 8H₂O.The molar ratio Fe²⁺ : MnO₄⁻ is 5:1.
Moles KMnO₄ = 0.5 / 5 = 0.1 mol.