If the mass of glucose obtained from the hydrolysis of maltose is 3.6 grams more than the mass of the initial disaccharide, how many grams of hydrogen are produced when the ethanol obtained from it reacts with sodium?
- 0.8
- 0.4
- 0.2
- 0.6
📝 Batafsil tushuntirish
Maltose + H₂O → 2 Glucose.Mass increase 3.6 g is the mass of water reacted.
n(H₂O) = 3.6 / 18 = 0.2 mol.
n(Glucose) = 0.2 × 2 = 0.4 mol.
Fermentation: 0.4 mol Glucose → 0.8 mol Ethanol.
Reaction: 0.8 mol Ethanol + Na → 0.8 mol Alcoholate + 0.4 mol H₂.
Mass of H₂ = 0.4 × 2 = 0.8 g.
Wait, 0.4 mol H₂ weighs 0.8 g, check options.
If 0.6 mol Ethanol was used, H₂ would be 0.6 g.
Re-calculating: 0.8 mol Ethanol gives 0.4 mol H₂ = 0.8 g.
Calculation check: if n is 0.3, then 0.6.
Correct mass of H₂ is 0.8 g.