In the following reaction: 3Cu + 8HNO₃(dilute) → 3Cu(NO₃)₂ + 2NO + 4H₂O, how many electrons are transferred in total per 3 moles of Copper?

  1. 2
  2. 4
  3. 6
  4. 8

📝 Batafsil tushuntirish

Copper changes from 0 to +2. For 3 moles of Cu, 3 * 2 = 6 electrons are lost. Nitrogen changes from +5 (in HNO₃) to +2 (in NO). For 2 moles of NO, 2 * 3 = 6 electrons are gained. The total transferred is 6.
4 / 50 (8%)
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