[Olympiad] The solubility product (Ksp) of AgCl is 1.8 x 10⁻¹⁰ at 25 °C. What is the molar solubility of AgCl in a 0.1 M NaCl solution?
- 1.34 x 10⁻⁵ M
- 1.8 x 10⁻⁹ M
- 1.8 x 10⁻⁸ M
- 9.0 x 10⁻¹⁰ M
📝 Batafsil tushuntirish
AgCl(s) ⇌ Ag⁺ + Cl⁻. Let solubility be 's'.[Ag⁺] = s, [Cl⁻] = 0.1 + s ≈ 0.1.
Ksp = [Ag⁺][Cl⁻] = s * 0.1 = 1.8 x 10⁻¹⁰.
s = 1.8 x 10⁻⁹ M.