Thermal decomposition of a mixture of 10.1 g of KNO₃ and 8.5 g of NaNO₃ releases how many liters of oxygen gas at STP?
- 1.12
- 2.24
- 3.36
- 4.48
📝 Batafsil tushuntirish
2KNO₃ → 2KNO₂ + O₂ (1 mol salt gives 0.5 mol O₂).2NaNO₃ → 2NaNO₂ + O₂ (1 mol salt gives 0.5 mol O₂).
Moles KNO₃ = 10.1 / 101 = 0.1 mol.
Moles NaNO₃ = 8.5 / 85 = 0.1 mol.
Total O₂ = (0.1 / 2) + (0.1 / 2) = 0.1 mol.
Volume = 0.1 × 22.4 = 2.24 L.