What is the mass percentage of Oxygen in Ethanol (C₂H₅OH)? (Ar: C=12, H=1, O=16)

Molar mass of C₂H₅OH = (2*12) + (6*1) + 16 = 46 g/mol. %O = (16 / 46) * 100 = 34.78%.

18 / 50 (36%)

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