What is the pH of a 0.0005 M solution of Barium Hydroxide?
- 3
- 11
- 10.7
- 12
📝 Batafsil tushuntirish
Ba(OH)₂ → Ba²⁺ + 2OH⁻.[OH⁻] = 2 * 0.0005 = 0.001 M.
pOH = -log(0.001) = 3.
pH = 14 - 3 = 11.
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