What is the pH of a 0.001 M solution of Barium Hydroxide Ba(OH)₂, assuming complete dissociation?
- 3.0
- 11.0
- 11.3
- 11.7
📝 Batafsil tushuntirish
[OH⁻] = 2 * [Ba(OH)₂] = 0.002 M.pOH = -log(0.002) ≈ 2.7.
pH = 14 - 2.7 = 11.3.
Bu mavzuda 50 Savollar. Bilimingizni sinab ko‘ring!
🔐 Test topshirish uchun tizimga kiringFan bo‘yicha barcha to‘plam va mavzularni ko‘ring: Bio+Chem
Fanga o‘tish →