What is the volume of 2 M KOH needed to react with 11.2 L of CO₂ (at STP) to form potassium carbonate?
- 500 ml
- 250 ml
- 1000 ml
- 100 ml
📝 Batafsil tushuntirish
2KOH + CO₂ → K₂CO₃ + H₂O.n(CO₂) = 11.2 / 22.4 = 0.5 mol.
n(KOH) needed = 0.5 * 2 = 1 mol.
Volume KOH = 1 mol / 2 M = 0.5 L = 500 ml.