What volume of 0.1 M KMnO₄ is required to react with 0.5 moles of Fe²⁺ in an acidic solution?
- 500 ml
- 100 ml
- 1000 ml
- 200 ml
📝 Batafsil tushuntirish
5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O.Moles MnO₄⁻ = 0.5 / 5 = 0.1 mol.
Volume = 0.1 / 0.1 = 1 L = 1000 ml.