What volume of 0.2 M KOH is required to fully neutralize 20 ml of 0.1 M H₂SO₄?
- 20 ml
- 10 ml
- 40 ml
- 5 ml
📝 Batafsil tushuntirish
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O.n(H₂SO₄) = 0.02 L * 0.1 M = 0.002 mol.
n(KOH) needed = 0.002 * 2 = 0.004 mol.
Volume KOH = 0.004 / 0.2 = 0.02 L = 20 ml.