When 0.2 mol of a divalent metal reacts with excess dilute sulfuric acid, 4.48 L of hydrogen gas (STP) is released. If the mass of the metal used was 11.2 g, identify the metal.
- Mg
- Fe
- Ca
- Zn
📝 Batafsil tushuntirish
M + H₂SO₄ → MSO₄ + H₂.n(H₂) = 4.48 / 22.4 = 0.2 mol.
Since n(Metal) = n(H₂) = 0.2 mol.
Molar mass = 11.2 / 0.2 = 56 g/mol.
The metal is Iron (Fe).