Combustion of 0.20 mol of an unknown alkane produced 17.92 L of CO₂ at STP. What is the molecular formula of the alkane?
- C₂H₆
- C₃H₈
- C₄H₁₀
- C₅H₁₂
📝 Detailed explanation
Moles of CO₂ = 17.92 / 22.4 = 0.80 mol.The ratio of Alkanes : CO₂ is 0.20 : 0.80, which is 1 : 4.
Each molecule of alkane must contain 4 carbon atoms. molecular formula = C₄H₁₀.