Determine the mass of aluminum that reacts with 200 g of a 20% solution of sulfuric acid.
- 7.35 g
- 11 g
- 3.67 g
- 14.7 g
📝 Detailed explanation
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂Mass H₂SO₄ = 200 × 0.2 = 40 g.
Moles H₂SO₄ = 40 / 98 ≈ 0.408 mol.
Moles Al = 0.408 × (2 / 3) ≈ 0.272 mol.
Mass Al = 0.272 × 27 ≈ 7.35 g.