How many liters of oxygen are needed for the complete combustion of 10 liters of a mixture consisting of 50% ethylene and 50% ethane?
- 30
- 32.5
- 35
- 25
📝 Detailed explanation
Volume C₂H₄ = 5 L. C₂H₄ + 3O₂ → 2CO₂ + 2H₂O. O₂ needed = 15 L.Volume C₂H₆ = 5 L. C₂H₆ + 3.5O₂ → 2CO₂ + 3H₂O. O₂ needed = 17.5 L.
Total O₂ = 15 + 17.5 = 32.5 L.