How many ml of 0.1 M KMnO₄ are needed to titrate 25 ml of 0.2 M FeSO₄ in an acidic medium?
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10 ml
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25 ml
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50 ml
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5 ml
📝 Detailed explanation
5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O.
n(Fe²⁺) = 0.025 * 0.2 = 0.005 mol.
n(MnO₄⁻) = n(Fe²⁺) / 5 = 0.001 mol.
V = 0.001 / 0.1 = 0.01 L = 10 ml.
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