[Olympiad] Calculate the pH of a 0.15 M solution of Methylamine (CH₃NH₂). (Kb = 4.4 × 10⁻⁴)
- 11.32
- 11.91
- 12.45
- 2.09
📝 Detailed explanation
[OH⁻] = √(Kb × C) = √(4.4 × 10⁻⁴ × 0.15) = 0.00812 M.pOH = -log(0.00812) = 2.09.
pH = 14 - 2.09 = 11.91.
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