[Olympiad] The rate of a reaction triples when the temperature is increased from 298 K to 308 K. Calculate the activation energy (Ea) in kJ/mol. (R = 8.314 J/mol·K)
- 42.5
- 82.9
- 120.4
- 15.8
📝 Detailed explanation
ln(k₂/k₁) = (Ea/R) × (1/T₁ - 1/T₂).ln(3) = (Ea / 8.314) × (1/298 - 1/308).
1.0986 = (Ea / 8.314) × (0.0001089).
Ea = (1.0986 × 8.314) / 0.0001089 = 83870 J/mol ≈ 83 kJ/mol.