Calculate the mass of a 10% solution of BaCl₂ required to react with 50 ml of a 2 M Na₂SO₄ solution to form a precipitate.
- 208 g
- 104 g
- 416 g
- 52 g
📝 Detailed explanation
BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaClMoles Na₂SO₄ = 0.05 × 2 = 0.1 mol.
Moles BaCl₂ needed = 0.1 mol.
Mass BaCl₂ = 0.1 × 208 = 20.8 g.
Mass of 10% solution = 20.8 / 0.1 = 208 g.