What volume of a 12.0 M HCl solution is needed to prepare 500 mL of a 2.0 M HCl solution?
-
41.7 mL
-
83.3 mL
-
120 mL
-
250 mL
📝 Detailed explanation
Using M₁V₁ = M₂V₂: (12.0)V₁ = (2.0)(500). V₁ = 1000 / 12 = 83.33 mL.
← Previous
→ Next
Space — Show answer
🎯 Take a test on the topic «Variant #4 of the University Scholarship Examination»
This topic contains 50 questions.
Test your knowledge!
🔐 Log in to take the test
📚 All tests by subject «Bio+Chem»
View all collections and topics in Bio+Chem
Go to subject →
