What is the limiting reagent when 10 g of Hydrogen (H₂) reacts with 40 g of Oxygen (O₂) to form water?
- Hydrogen
- Oxygen
- Both are consumed completely
- Water
📝 Detailed explanation
2H₂ + O₂ → 2H₂O. Moles H₂ = 10/2 = 5 mol. Moles O₂ = 40/32 = 1.25 mol.According to stoichiometry, 1.25 mol O₂ requires only 2.5 mol H₂. Since we have 5 mol H₂, Oxygen is the limiting reagent.