A sample of an ideal gas occupies 4.0 L at 2.0 atm and 273 K. What will be its volume at 1.0 atm and 546 K?
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2.0 L
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8.0 L
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16.0 L
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4.0 L
📝 Detailed explanation
Using the combined gas law (P₁V₁/T₁ = P₂V₂/T₂): (2.0 * 4.0) / 273 = (1.0 * V₂) / 546.
8.0 / 273 = V₂ / 546 => V₂ = (8.0 * 546) / 273 = 16.0 L.
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