How many atoms are contained in 28 grams of pure Iron (Fe)? (Atomic mass of Fe = 56 g/mol, Nₐ = 6.02 × 10²³)
- 3.01 × 10²²
- 3.01 × 10²³
- 6.02 × 10²³
- 1.20 × 10²⁴
📝 Batafsil tushuntirish
Moles of Fe = 28g / 56g/mol = 0.5 moles.Number of atoms = 0.5 × 6.02 × 10²³ = 3.01 × 10²³.