How many ml of 0.1 M KMnO₄ are needed to titrate 25 ml of 0.2 M FeSO₄ in an acidic medium?
- 10 ml
- 25 ml
- 50 ml
- 5 ml
📝 Batafsil tushuntirish
5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O.n(Fe²⁺) = 0.025 * 0.2 = 0.005 mol.
n(MnO₄⁻) = n(Fe²⁺) / 5 = 0.001 mol.
V = 0.001 / 0.1 = 0.01 L = 10 ml.