In the reaction N₂ + 3H₂ → 2NH₃, if 28 g of Nitrogen reacts with excess Hydrogen and produces 17 g of Ammonia, what is the percentage yield? (Atomic weights: N=14, H=1)
- 25%
- 50%
- 75%
- 100%
📝 Batafsil tushuntirish
Moles of N₂ = 28g / 28g/mol = 1 mol.Theoretical yield of NH₃ = 2 moles (from stoichiometry).
Theoretical mass = 2 mol × 17g/mol = 34 g.
Yield % = (Actual / Theoretical) × 100 = (17 / 34) × 100 = 50%.